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post #1 of 3 Old 02-19-2007, 09:29 PM Thread Starter
More math help, please answer fast

A=H(x+y)/2, make it y=

How do you find the distance between two points, (2,5) and (-4,3)

True or false:
A relation is a function if each input has only one output
Another name for the set of outputs of a function is the domain of the function.

The formula h=-16t squared + 96t gives the height of h in feet of a projectile at time t seconds. At what time(s) is the projectile 144 feet above the ground?
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post #2 of 3 Old 02-19-2007, 10:48 PM
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Re: More math help, please answer fast

Quote:
Originally Posted by musho3210
How do you find the distance between two points, (2,5) and (-4,3)
I am giving my best guess, I had math last semester, but I got an F because I never did homework, so dont trust my answer 100%

2= x1 and 5= y1
-4=x2 and 3=y2

so d=(square root of all the next im going to type) (x2-x1)squared + (y2-y1)squared

so THEN d=(square root of all) (-4-2)squared + (3-5)squared

can you get it from there?

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post #3 of 3 Old 02-20-2007, 02:39 AM
Re: More math help, please answer fast

Quote:
Originally Posted by musho3210
A=H(x+y)/2, make it y=

y=(2A/H)-X

How do you find the distance between two points, (2,5) and (-4,3)

((2-(-4)^2+(5-3)^2)^.5

True or false:
A relation is a function if each input has only one output
Another name for the set of outputs of a function is the domain of the function.

These are simple: Look in your book!!

The formula h=-16t squared + 96t gives the height of h in feet of a projectile at time t seconds. At what time(s) is the projectile 144 feet above the ground?

Look in your book for the quadratic formula or
http://www.purplemath.com/modules/quadform.htm
0=-16t^2+96t-144
a=-16
b=96
c=-144



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