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oh i was way off. But it was a hard one and it was nothing like my teacher had told me to study. But thanks anyway, you learn something new everyday.
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The other one is a pain in the butt and I feel bad for throwing it at you. It's not even particularly hard, just tedious, with all sorts of little things going on.
I mean, obviously Jerry is going to go 500 miles at 80 mph and come to a dead stop. 50/8 = 25/4 = 12.5/2 = 6 hours 15 minutes later.
Mario will do that same 500 miles at 60, so 50/6 = 25/3 = 8 hours 20 minutes, but he had to stop and gas up for 10 minutes (at a cost of $80), so Jerry sits on his duff and cusses Dame Fortuna for 2 hours 15 minutes. It's all like that. (Incidentally, when I went back and checked this, I caught and corrected an error I made.)
In 1500 miles Mario will need to fill up 5 times, for $400, so a 10% profit would be $440. Jerry will want to fly home, I think. He'll do the remaining 1000 miles at 50 MPH, so it'll take 20 hours (which is a respectable speed to go for that long  I know, I've driven 20 hours out of Austin to go 1000 Miles), but add 8 hours 20 minutes for the first leg, plus 50 minutes for gassing up, plus 20 to hitch up the car, so a total of 29 hours 30 minutes. Let's hope Mario has lots of strong coffee and a very strong bladder.
I mean, obviously Jerry is going to go 500 miles at 80 mph and come to a dead stop. 50/8 = 25/4 = 12.5/2 = 6 hours 15 minutes later.
Mario will do that same 500 miles at 60, so 50/6 = 25/3 = 8 hours 20 minutes, but he had to stop and gas up for 10 minutes (at a cost of $80), so Jerry sits on his duff and cusses Dame Fortuna for 2 hours 15 minutes. It's all like that. (Incidentally, when I went back and checked this, I caught and corrected an error I made.)
In 1500 miles Mario will need to fill up 5 times, for $400, so a 10% profit would be $440. Jerry will want to fly home, I think. He'll do the remaining 1000 miles at 50 MPH, so it'll take 20 hours (which is a respectable speed to go for that long  I know, I've driven 20 hours out of Austin to go 1000 Miles), but add 8 hours 20 minutes for the first leg, plus 50 minutes for gassing up, plus 20 to hitch up the car, so a total of 29 hours 30 minutes. Let's hope Mario has lots of strong coffee and a very strong bladder.
Logic is only the beginning of wisdom
Quote:
Originally Posted by tophat665
The other one is a pain in the butt and I feel bad for throwing it at you. It's not even particularly hard, just tedious, with all sorts of little things going on.
I mean, obviously Jerry is going to go 500 miles at 80 mph and come to a dead stop. 50/8 = 25/4 = 12.5/2 = 6 hours 15 minutes later.
Mario will do that same 500 miles at 60, so 50/6 = 25/3 = 8 hours 20 minutes, but he had to stop and gas up for 10 minutes (at a cost of $80), so Jerry sits on his duff and cusses Dame Fortuna for 2 hours 15 minutes. It's all like that. (Incidentally, when I went back and checked this, I caught and corrected an error I made.)
In 1500 miles Mario will need to fill up 5 times, for $400, so a 10% profit would be $440. Jerry will want to fly home, I think. He'll do the remaining 1000 miles at 50 MPH, so it'll take 20 hours (which is a respectable speed to go for that long  I know, I've driven 20 hours out of Austin to go 1000 Miles), but add 8 hours 20 minutes for the first leg, plus 50 minutes for gassing up, plus 20 to hitch up the car, so a total of 29 hours 30 minutes. Let's hope Mario has lots of strong coffee and a very strong bladder.
I mean, obviously Jerry is going to go 500 miles at 80 mph and come to a dead stop. 50/8 = 25/4 = 12.5/2 = 6 hours 15 minutes later.
Mario will do that same 500 miles at 60, so 50/6 = 25/3 = 8 hours 20 minutes, but he had to stop and gas up for 10 minutes (at a cost of $80), so Jerry sits on his duff and cusses Dame Fortuna for 2 hours 15 minutes. It's all like that. (Incidentally, when I went back and checked this, I caught and corrected an error I made.)
In 1500 miles Mario will need to fill up 5 times, for $400, so a 10% profit would be $440. Jerry will want to fly home, I think. He'll do the remaining 1000 miles at 50 MPH, so it'll take 20 hours (which is a respectable speed to go for that long  I know, I've driven 20 hours out of Austin to go 1000 Miles), but add 8 hours 20 minutes for the first leg, plus 50 minutes for gassing up, plus 20 to hitch up the car, so a total of 29 hours 30 minutes. Let's hope Mario has lots of strong coffee and a very strong bladder.
OMG!!!!
http://216.55.166.77/userpix/51_Flatcam_sig_2_1.jpg
Flatcam1
thanks guys for letting me be a mod! evan though it was a short while, i am still very grate full. :)
Oh! ( wipes sweat of forehead )
Thats good LOL
Thats good LOL
http://216.55.166.77/userpix/51_Flatcam_sig_2_1.jpg
Flatcam1
thanks guys for letting me be a mod! evan though it was a short while, i am still very grate full. :)
Let me suggest you google Algebra I Word Problems.
Basically you're going to get a couple different kinds of problems. Most of them will reduce to line equations, y=mx+b, where y is the height, x the width, m the slope, and b the height at 0. Remember that, if you are given two points (x1,y1) and (x2,y2), you can figure out the slope with m=(y1y2)/(x1x2). Then you can take that and plug it into b=ymx. Now you'll have a line equaion you can use to find any point on the line.
Sometimes you're going to have two intersecting line equations, like with the balloon problem.
The trick is to look the word problem over and try and pick out the lines you need to write equations for.
My problem is that I have gone through Differential Equations (which I failed), and most of the problems that come to my mind require at least trig if not calculus to solve. Sorry about that.
Google is your friend here. Good luck and Godspeed.
Basically you're going to get a couple different kinds of problems. Most of them will reduce to line equations, y=mx+b, where y is the height, x the width, m the slope, and b the height at 0. Remember that, if you are given two points (x1,y1) and (x2,y2), you can figure out the slope with m=(y1y2)/(x1x2). Then you can take that and plug it into b=ymx. Now you'll have a line equaion you can use to find any point on the line.
Sometimes you're going to have two intersecting line equations, like with the balloon problem.
The trick is to look the word problem over and try and pick out the lines you need to write equations for.
My problem is that I have gone through Differential Equations (which I failed), and most of the problems that come to my mind require at least trig if not calculus to solve. Sorry about that.
Google is your friend here. Good luck and Godspeed.
Logic is only the beginning of wisdom
Quote:
Originally Posted by musho3210
no, like RxT=D
Rate times Time equals distance
Rate times Time equals distance

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