Math exam help
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Math exam help

This is a discussion on Math exam help within the Off Topic Discussions forums, part of the The Tropical Fish Keeping Community category; --> This friday i have an Honors Algerbra math semester exam. I am quite confident about everything except word problems. Can someone give me some? ...

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Old 01-24-2007, 06:08 PM   #1
 
Math exam help

This friday i have an Honors Algerbra math semester exam. I am quite confident about everything except word problems. Can someone give me some? Make sure you know the answer too. Heres and example

Tom was in a hot air baloon 20,000ft in the air. He was decending at a rate of 10ft per second. Jim was 2,000 ft in the air and was acsending at 2 ft per second. When do they both meet?
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Old 01-24-2007, 07:34 PM   #2
 
I am good in math but when it comes to that type forget it. It would take me forever.
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Old 01-24-2007, 07:36 PM   #3
 
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I Suck at Math.
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Old 01-24-2007, 07:48 PM   #4
 
oh, well i hope someone helps me out.... all i have are notes but nothing to actually work on.
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Old 01-24-2007, 09:49 PM   #5
 
u mean like 3y+3tb+9y+5tb+8ab=?
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Old 01-24-2007, 09:57 PM   #6
 
no, like RxT=D

Rate times Time equals distance
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Old 01-24-2007, 10:35 PM   #7
 
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OK, Tom is at 20K dropping 10/sec. Bill at 2K rising 2/sec.

So the position of Tom at an arbitrary time t is T(t) = 20K - 10t and the Position of Bill at t, B(t) = 2K + 2t.

So they meet when T(t) = B(t) or when 20K-10t = 2K +2t. Therefore 18K = 12t. 18000/12 = t = 1500 seconds.

Then go back and check.
2000 + 2(1500) = 5000
20000 - 10(1500) = 5000

If you plot it out on graph paper, with your y axis in thousands of feet and your x axis in hundreds of seconds, Tom's line starts at (0,20) and drops at a 45 degree angle toward (20,0), Bill's line starts at (0,2) and rises to (15,5) where it meets Tom's line.

Quack Ergo Duck.

Here's another one for you. Hotdogs come in packs of 8. Buns come in Packs of 10. On average, people eat 1 2/3 hotdogs at a sitting. What's the smallest number of people, packs of hotdogs, and packs of buns greater than zero do you need to bring together for no leftovers.

Or Jerry (who was a racecar driver) and Mario (a plumber) take of from Duluth in a sports car and a tow truck respectively. Jerry has enough gas to get him 500 miles (and no way to get more), and averages 80 mph. Mario averages 60 in his tow truck when he's not pulling a car, and 50 when he is, and can get 300 miles without regassing. It takes him 10 minutes to gas up for $80 and 20 to hitch up a car. Austin is 1500 miles. How long until he and Jerry pull into the Western Union in Austin, How long does Jerry sit by the side of the road waiting for Mario to come pick him up, and How much does Mario charge Jerry for the tow to make a 10% profit on gas.

Scratch the last one - I just realized there was some trig involved.
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Old 01-24-2007, 10:58 PM   #8
 
R.T=D

H( 8 )
B(10)
1 2/3p

8h+10b=1 2/3p
-8h -8h
______________
10b= 1 2/3p-8h
---- ------------
10 10
________________

B= 1/6p-.8

Plug in B

8h+10(1/6p-.8h)=1 2/3p

Distribute

8h+1 2/3p-8h=1 2/3p

The h's cancel out which leaves

1 2/3p=1 2/3p

Which means any real number, right?



I have an extremly strong feeling i did this wrong but i got

No solution

P.S i get points for showing work.

EDIT: WAIT, i got any real number, not no solution.
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Old 01-24-2007, 11:15 PM   #9
 
its any real number as long as they all equal the same, like

h=1 pack
b=1 pack
p=1 person


h=2 pack
b=2 pack
p=2 person


h=12 pack
b=12 pack
p=12 person
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Old 01-24-2007, 11:30 PM   #10
 
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Actually, start by figuring out the minimum number of packs of hotdogs and buns you'll need. So the first multiple of 8 that's also divisible by 10 is 40. 5 packs of hotdogs, 4 of buns. 1 2/3 is 5/3. Dividing by 5/3 is the same as multiplying by 3/5. 40*3/5=24. So 40 hotdogs and buns in 5 and 4 packs respectively devoured by 24 people.
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